2m^2-2m-1.5=0

Solution for 2m^2-2m-1.5=0 equation:

2m^2-2m-1.5=0

a = 2; b = -2; c = -1.5;
Δ = b2-4ac
Δ = -22-4·2·(-1.5)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-4}{2*2}=\frac{-2}{4}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+4}{2*2}=\frac{6}{4}
=1+1/2
$